# 7.19: In example 7.5 (page 258) the two accelerations are given by equations 7.66 and 7.67….

7.19:
In example 7.5 (page 258) the two accelerations are given by
equations 7.66 and 7.67. Check that the acceleration of the block
is given correctly in the limit M — 0. [You need to find the
components of this acceleration relative to the table]

I am mostly just confused on what it means to find the
components relative to the table?
Figure 7.8 A block of mass m slides down a wedge of mass M, which is free to slide over the horizontal table. 92 = – _osa, (7.66) M + m from (7.65) and solve for qi: _sina 1. mcosa q=- (7.67) 1 – M +m

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